An oxidation reduction reaction that is also a synthesis reaction


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An oxidation-reduction reaction that is also a synthesis reaction

A. 2Mg(s) + O2(g) --> 2 MgO(s)
B. Pb^2+(aq) + CrO4^2-(aq)--> PbCrO4(s)

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Answer:

The oxidation reduction reaction which is also a synthesis reaction is:

A.2Mg(s)+O_{2}(g)\rightarrow 2MgO(s).

Explanation:

A Synthesis reaction is a reaction in which two or more reactants combine to form a single product.

A redox reaction(oxidation reduction) is a reaction in which one species is oxidised and one is reduced simultaneously.

Oxidation: Loss of electron or increase in oxidation state

Reduction: Gain of electron or decrease in oxidation state

In both cases A,B two reactant are combining to give a single compound.So both are synthesis reaction.

A.2Mg(s)+O_{2}(g)\rightarrow 2MgO(s) is a redox reaction :

Oxidation of Mg :2Mg(s)\rightarrow 2Mg^{2+}+4e^{-}

(increase in oxidation state of Mg from 0 to +2)

Reduction of Oxygen: O_{2}(g)+4e^{-}\rightarrow 2O^{2-}

(decrease in oxidation state of O from 0 to -2)

on combining above half-reactions:

2Mg(s)+O_{2}(g)\rightarrow 2MgO(s)

Its both redox and synthesis reaction.

But there is no change in oxidation states of elements in Reaction B

Pb^{2+}(aq)+CrO_{4}^{2-}\rightarrow PbCrO_{4}(s)

oxidation state of Pb is (+2) in both Pb^{2+}and PbCrO_{4}:

Pb^{2+}\rightarrow PbCrO_{4}

Cr has (+6) oxidation state in both CrO_{4}{2-} and  PbCrO_{4}:

CrO_{4}{2-}\rightarrow PbCrO_{4}

No change in oxidation state so no loss/gain of electrons .Hence not a redox reaction

B. is not a oxidation reduction reaction ,its just a synthesis reaction.

Hence,

The oxidation reduction reaction which is also a synthesis reaction is:

A.2Mg(s)+O_{2}(g)\rightarrow 2MgO(s).


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